Show that at absolute temperature T, the quantity KT is roughly equal to the mean energy per degree of freedom - स्वागत svaagat सवाल और जवाब savaal aur javaab, in this article entitled Show that at absolute temperature T, the quantity KT is roughly equal to the mean energy per degree of freedom, I will discuss about Physics, while also providing the right information to be useful for my friend , for I share the information based on what I know , if there is a mistake you can leave a comment or contact us on the menu that has been provided.

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लेख का शीर्षक lekh ka sheershak: Show that at absolute temperature T, the quantity KT is roughly equal to the mean energy per degree of freedom

Show that at absolute temperature T, the quantity KT is roughly equal to the mean energy per degree of freedom

Answer:

Solutions 

• Temperature ~ Average KE of each particle

• Particles have different speeds

• Gas Particles are in constant RANDOM motion

• Average KE of each particle is: 3/2 kT

This subject touches upon statistical mechanics, which is a deep subject.  Pressure is force per unit area. Force is rate of change of momentum. That is, the amount of momentum transferred to a wall per second. This is achieved through the gas molecules colliding with the wall.  A molecule of mass (m) and velocity (v) facing the wall will change to velocity −v after colliding with the wall (assuming that the collision is elastic). Thus momentum of the molecule changes from to mv to −mv.

The momentum transferred to the wall per molecule collision is therefore = mv−(−mv)=2mv If the wall area is A, the number of collisions on this wallin time Δt is ρAvΔt where ρ=(N/V) is the number density of the gas molecules. We therefore see that the total momentum transferred to the wall of area A in time Δt is equal to 2mv⋅ρAvΔt Dividing by Δt to get the rate change of momentum or force, then dividing by A to get pressure, we have = P=2ρmv²=2(N/V)mv² .

We must next replace by v by vₐv, which means averaging it over the different velocities of the different molecules. So far,  vₐv has a direction pointing toward the wall. But actual molecules are moving in all kinds of directions, so in the average, only 1/6 of the molecules are moving in that direction. This cuts down the answer for P by a factor of 6. So finally, we get = P=1/3(N/V)mv²av

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तुम सिर्फ पढ़ा है tum sirph padha hai Show that at absolute temperature T, the quantity KT is roughly equal to the mean energy per degree of freedom और इस लेख के बाद स्थायी शामिल करने के लिए उद्धृत किया जा सकता aur is lekh ke baad sthaayee shaamil karane ke lie uddhrt kiya ja sakata https://axaj.blogspot.com/2016/08/show-that-at-absolute-temperature-t.html यह लेख एक साथी खोज नहीं है, तो yah lekh ek saathee khoj nahin hai, to Physics शायद नीचे लेख पाल मदद कर सकते हैं shaayad neeche lekh paal madad kar sakate hain.